To prove zero equals infinity

let
u=5,v=4,x=zero,y=infinity,z=1

firstly take

- 20 = - 20
which can be written as
=> 16-36 = 25-45
by adding (81/4) on both sides we get
=> 16-36+(81/4) = 25-45+(81/4)
by writing the above eqn like this
=> ((4)2 -(2*4*(9/2)) +(9/2)2) = ((5)2 -(2*5*(9/2)) +(9/2)2)
which is of the form
=> (a-b)2 = a2 + b2 -2ab
here
=> a = 4 a = 5
b = 9/2 b = 9/2
from this we can write the above equation as
=> (4-(9/2)) 2 = (5-(9/2))2
by taking square root on both sides we get
=> +- (4-(9/2)) = +- (5-(9/2))
according to axioms when both sides are equal and having the same signs on both sides then both sides are positively equated to each other
=> 4 - (9/2) = 5 - (9/2)
by shifting -(9/2) from left side to right side we get
=> 4 = 5 - (9/2) +(9/2)
then as 9/2 gets cancelled we get
=> 4 = 5
then substituting corresponding variables for result we get
=> v = u
then by shifting v we get
=> 0 = u-v ........................................eqn1
here by entering values of u and v we prove that 0=1
i.e 0 = 5-4 => 0 = 1 ..............................eqn2
again here by substituting the corresponding variables to result we get
=> x = z
here by cross multiplying x to z quadrant we get
=> 1 = (z/x)
then again by substituting corresponding values of z and x we get
=> 1 = (1/0)
as we know that (1/0) is infinity
=> 1 = infinity ................................eqn3
again by representing result with corresponding variables we get
=> z = y
then by mathematical laws
if a=b and b=c then a=c we get
=>x = y
here by substituting there values we get
=> zero = infinity
hence proved.

Extra tips--->
1)by using eqn 2 any number can be proved to zero (i.e by multiplying both sides by any number)
2)by using eqn 3 any number can be proved to infinity (i.e by multiplying both sides by any number)



isn't this amazing