Monday, November 3, 2008

To prove 4 = 5

let

- 20 = - 20
which can be written as
=> 16-36 = 25-45
by adding (81/4) on both sides we get
=> 16-36+(81/4) = 25-45+(81/4)
by writing the above eqn like this
=> ((4)2 -(2*4*(9/2)) +(9/2)2) = ((5)2 -(2*5*(9/2)) +(9/2)2)
which is of the form
=> (a-b)2 = a2 + b2 -2ab
here
=> a = 4 a = 5
b = 9/2 b = 9/2
from this we can write the above equation as
=> (4-(9/2)) 2 = (5-(9/2))2
by taking square root on both sides we get
=> +- (4-(9/2)) = +- (5-(9/2))
according to axioms when both sides are equal and having the same signs on both sides then both sides are positively equated to each other
=> 4 - (9/2) = 5 - (9/2)
by shifting -(9/2) from left side to right side we get
=> 4 = 5 - (9/2) +(9/2)
then as 9/2 gets cancelled we get
=> 4 = 5



isn't this amazing


3 comments:

  1. Ah fun. You at least got me to think for a bit to find the error in your logic.

    ReplyDelete
  2. (4-9/2)==(4-4.5)==(-0.5)

    We should not take the square root of the negative number

    ReplyDelete
  3. I Will proove it in the easyiest way

    4*0 = 5*0
    4 = 5

    Dont clap,man
    no publicity please!
    And One more thing
    ((4)2 -(2*4*(9/2)) +(9/2)2) is not equal to ((5)2 -(2*5*(9/2)) +(9/2)2)

    ReplyDelete